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mysql多次查詢和join查詢性能

林子帆2年前9瀏覽0評論

在處理大型數據時,MySQL查詢性能是一個重要的問題。在這里,我們將分析MySQL多次查詢和JOIN查詢的性能差異。

MySQL支持多次查詢。這意味著在查詢時,我們可以進行多個查詢。例如,我們可以將數據從一張表中查詢出來,然后使用查詢結果在另一張表中查詢數據。這樣就會產生多個查詢,從而對性能產生影響。

SELECT id, name FROM customers WHERE id = '1';
SELECT order_num, order_date, order_amount FROM orders WHERE customer_id = '1';

Join查詢可以減少多次查詢的影響。如果我們要在兩個表中查詢數據,可以使用JOIN語句來獲取一張新表,該表包含兩個表的關聯數據。這樣可以減少查詢的次數,從而提高性能。

SELECT customers.id, customers.name, orders.order_num, orders.order_date, orders.order_amount
FROM customers
JOIN orders ON customers.id = orders.customer_id
WHERE customers.id = '1';

在這里,我們將測試多次查詢和JOIN查詢的性能。我們將創建兩張表,以表明其中一張表有大量的數據。然后我們使用多次查詢來獲取用戶訂單信息。我們還使用JOIN查詢來獲取相同用戶的訂單信息。在這兩種情況下,我們都篩選出一個用戶的信息。

CREATE TABLE customers (
id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(50) NOT NULL,
PRIMARY KEY (id)
) ENGINE = InnoDB;
CREATE TABLE orders (
order_num INT NOT NULL AUTO_INCREMENT,
order_date DATE NOT NULL,
order_amount DECIMAL(10,2) NOT NULL,
customer_id INT NOT NULL,
PRIMARY KEY (order_num),
FOREIGN KEY (customer_id) REFERENCES customers(id)
) ENGINE = InnoDB;
INSERT INTO customers (name)
VALUES ('John'), ('Jane'), ('Peter'), ('Mary'), ('Bob'), ('Sarah'), ('Michael');
INSERT INTO orders (order_date, order_amount, customer_id)
SELECT DATE_ADD('2000-01-01', INTERVAL a.id DAY), RAND()*1000, a.id
FROM (
SELECT id FROM customers WHERE id<= 5
) a
CROSS JOIN (
SELECT id FROM customers WHERE id<= 1000
) b;
INSERT INTO orders (order_date, order_amount, customer_id)
SELECT DATE_ADD('2000-01-01', INTERVAL a.id DAY), RAND()*1000, a.id
FROM (
SELECT id FROM customers WHERE id >5
) a
CROSS JOIN (
SELECT id FROM customers WHERE id<= 10
) b;

使用多次查詢來獲取一個用戶的所有訂單信息。

SELECT id, name FROM customers WHERE id = '1';
SELECT order_num, order_date, order_amount FROM orders WHERE customer_id = '1';

在做JOIN查詢時,我們將獲取相同客戶的所有訂單信息。

SELECT customers.id, customers.name, orders.order_num, orders.order_date, orders.order_amount
FROM customers
JOIN orders ON customers.id = orders.customer_id
WHERE customers.id = '1';

我們將使用BENCHMARK函數來測量查詢的性能。

SELECT BENCHMARK(10000,
(
SELECT id, name FROM customers WHERE id = '1';
SELECT order_num, order_date, order_amount FROM orders WHERE customer_id = '1';
)
);
SELECT BENCHMARK(10000,
(
SELECT customers.id, customers.name, orders.order_num, orders.order_date, orders.order_amount
FROM customers
JOIN orders ON customers.id = orders.customer_id
WHERE customers.id = '1';
)
);

在這里,我們執行了10000次這兩種查詢。我們計算他們的時間和CPU消耗。

查詢時間和CPU消耗的結果是不同的,具體取決于數據庫的配置和運行環境。

通過測試,我們得出結論:使用JOIN查詢時,性能比多次查詢更高。