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mysql 查找兩次不及格

在MySQL中,我們可以使用子查詢來查找學(xué)生連續(xù)兩次不及格的情況。下面是一個(gè)簡(jiǎn)單的例子:

SELECT s1.student_id, s1.course_id, s1.grade, s2.grade 
FROM scores s1, scores s2 
WHERE s1.student_id = s2.student_id 
AND s1.course_id = s2.course_id 
AND s1.grade < 60 AND s2.grade < 60 
AND s1.year = s2.year AND 
((s1.semester = s2.semester AND s1.week = s2.week-1) 
OR (s1.semester = s2.semester-1 AND s2.week = 52 
AND s1.week = 1))

這個(gè)查詢使用了兩個(gè)scores表的實(shí)例,它們都包含了學(xué)生的成績(jī)信息。我們通過s1表和s2表中的連接條件找到同一學(xué)生在同一課程中的成績(jī)信息。然后,我們使用WHERE語句過濾不及格成績(jī),并且確保這些成績(jī)是連續(xù)的兩個(gè)學(xué)期。

如果你想查詢?nèi)_B續(xù)兩次不及格的學(xué)生,可以這樣寫:

SELECT DISTINCT s1.student_id 
FROM scores s1, scores s2 
WHERE s1.student_id = s2.student_id 
AND s1.course_id = s2.course_id 
AND s1.grade < 60 AND s2.grade < 60 
AND s1.year = s2.year AND 
((s1.semester = s2.semester AND s1.week = s2.week-1) 
OR (s1.semester = s2.semester-1 AND s2.week = 52 
AND s1.week = 1))

在這個(gè)查詢中,我們只查詢學(xué)生學(xué)號(hào),使用DISTINCT關(guān)鍵字去重復(fù)。