apierror60001怎么解決？

package org.oms.wechat.utils; /** * 企業(yè)號根據(jù)錯誤碼返回錯誤信息類 * @author sunlight * */ public class ErrorCodeText { public static String errorMsg(int errorcode) { String errmsg = ""; switch (errorcode) { case -1: errmsg = "系統(tǒng)繁忙 "; break; case 0: errmsg = "請求成功 "; break; case 40001: errmsg = "獲取access_token時Secret錯誤，或者access_token無效 "; break; case 40002: errmsg = "不合法的憑證類型"; break; case 40003: