9給一個不多于5位的正整數？

#include<stdio.h>

int main()

{ int num,a1,a2,a3,b1,b2,b3,b4,c1,c2,c3,c4,c5,d1,d2,d3,d4,d5,d6;

printf("輸入數字為:");

scanf("%d",&num);

if(0<num && num<=9)

{printf("該數字是一位數\n");

printf("打印的數字%d\n",num);

printf("倒序=%d\n",num);

}

else

if(10<=num && num<=99)

{printf("該數字是二位數\n");

a1=num/10;

a2=num%10;

a3=10*a2+a1;

printf("打印的數字是%d %d\n",a1,a2);

printf("倒序數是%d\n",a3);

}

else

if(100<=num && num<=999)

{printf("該數字是三位數\n");

b1=num/100;

b2=(num-b1*100)/10;

b3=(num-b1*100)%10;

b4=(100*b3+10*b2+b1);

printf("打印的數字是%d %d %d\n",b1,b2,b3);

printf("倒序數是%d\n",b4);

}

else

if(1000<=num && num<=9999)

{printf("該數字是四位數\n");

c1=num/1000;

c2=(num-c1*1000)/100;

c3=(num-c1*1000-c2*100)/10;

c4=(num-c1*1000-c2*100)%10;

c5=(c4*1000+c3*100+c2*10+c1);

printf("打印的數字是%d %d %d %d\n",c1,c2,c3,c4);

printf("倒序數是%d\n",c5);

}

else

if(10000<=num && num<=99999)

{printf("該數字是五位數\n");

d1=num/10000;

d2=(num-d1*10000)/1000;

d3=(num-d1*10000-d2*1000)/100;

d4=(num-d1*10000-d2*1000-d3*100)/10;

d5=(num-d1*10000-d2*1000-d3*100-d4*10)%10;

d6=d5*10000+d4*1000+d3*100+d2*10+d1;

printf("打印的數字是%d %d %d %d %d\n",d1,d2,d3,d4,d5);

printf("倒序數是%d\n",d6);

}

else

printf("輸入數據錯誤");

return 0;

}